(2x-1)/6+(4x+1)/8=1/3x

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Solution for (2x-1)/6+(4x+1)/8=1/3x equation:



(2x-1)/6+(4x+1)/8=1/3x
We move all terms to the left:
(2x-1)/6+(4x+1)/8-(1/3x)=0
Domain of the equation: 3x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(2x-1)/6+(4x+1)/8-(+1/3x)=0
We get rid of parentheses
(2x-1)/6+(4x+1)/8-1/3x=0
We calculate fractions
There is no solution for this equation

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