(2x-1)=2(6x-3)+4x-2

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Solution for (2x-1)=2(6x-3)+4x-2 equation: 



(2x-1)=2(6x-3)+4x-2

We move all terms to the left:

(2x-1)-(2(6x-3)+4x-2)=0

We get rid of parentheses

2x-(2(6x-3)+4x-2)-1=0



We calculate terms in parentheses: -(2(6x-3)+4x-2), so:

2(6x-3)+4x-2

We add all the numbers together, and all the variables

4x+2(6x-3)-2

We multiply parentheses

4x+12x-6-2

We add all the numbers together, and all the variables

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

2x-16x+8-1=0

We add all the numbers together, and all the variables

-14x+7=0

We move all terms containing x to the left, all other terms to the right

-14x=-7

x=-7/-14

x=1/2

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