(2x-1)=5(3x-2)

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Solution for (2x-1)=5(3x-2) equation:



(2x-1)=5(3x-2)
We move all terms to the left:
(2x-1)-(5(3x-2))=0
We get rid of parentheses
2x-(5(3x-2))-1=0
We calculate terms in parentheses: -(5(3x-2)), so:
5(3x-2)
We multiply parentheses
15x-10
Back to the equation:
-(15x-10)
We get rid of parentheses
2x-15x+10-1=0
We add all the numbers together, and all the variables
-13x+9=0
We move all terms containing x to the left, all other terms to the right
-13x=-9
x=-9/-13
x=9/13

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