(2x-1.4)x=16

Solution for (2x-1.4)x=16 equation:

(2x-1.4)x=16

We move all terms to the left:

(2x-1.4)x-(16)=0

We multiply parentheses

2x^2-1.4x-16=0

a = 2; b = -1.4; c = -16;
Δ = b2-4ac
Δ = -1.42-4·2·(-16)
Δ = 129.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.4)-\sqrt{129.96}}{2*2}=\frac{1.4-\sqrt{129.96}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.4)+\sqrt{129.96}}{2*2}=\frac{1.4+\sqrt{129.96}}{4}
$