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(2x-10)(4x+16)=180
We move all terms to the left:
(2x-10)(4x+16)-(180)=0
We multiply parentheses ..
(+8x^2+32x-40x-160)-180=0
We get rid of parentheses
8x^2+32x-40x-160-180=0
We add all the numbers together, and all the variables
8x^2-8x-340=0
a = 8; b = -8; c = -340;
Δ = b2-4ac
Δ = -82-4·8·(-340)
Δ = 10944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10944}=\sqrt{576*19}=\sqrt{576}*\sqrt{19}=24\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-24\sqrt{19}}{2*8}=\frac{8-24\sqrt{19}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+24\sqrt{19}}{2*8}=\frac{8+24\sqrt{19}}{16} $
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