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(2x-10)(4x+46)=3x
We move all terms to the left:
(2x-10)(4x+46)-(3x)=0
We add all the numbers together, and all the variables
-3x+(2x-10)(4x+46)=0
We multiply parentheses ..
(+8x^2+92x-40x-460)-3x=0
We get rid of parentheses
8x^2+92x-40x-3x-460=0
We add all the numbers together, and all the variables
8x^2+49x-460=0
a = 8; b = 49; c = -460;
Δ = b2-4ac
Δ = 492-4·8·(-460)
Δ = 17121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{17121}}{2*8}=\frac{-49-\sqrt{17121}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{17121}}{2*8}=\frac{-49+\sqrt{17121}}{16} $
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