(2x-10)+(4x-20)=12

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Solution for (2x-10)+(4x-20)=12 equation: 



(2x-10)+(4x-20)=12

We move all terms to the left:

(2x-10)+(4x-20)-(12)=0

We get rid of parentheses

2x+4x-10-20-12=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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