(2x-10)+(x+22)=136

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Solution for (2x-10)+(x+22)=136 equation: 



(2x-10)+(x+22)=136

We move all terms to the left:

(2x-10)+(x+22)-(136)=0

We get rid of parentheses

2x+x-10+22-136=0

We add all the numbers together, and all the variables

3x-124=0

We move all terms containing x to the left, all other terms to the right

3x=124

x=124/3

x=41+1/3

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