(2x-10)+(x+8)=(4x-28)

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Solution for (2x-10)+(x+8)=(4x-28) equation: 



(2x-10)+(x+8)=(4x-28)

We move all terms to the left:

(2x-10)+(x+8)-((4x-28))=0

We get rid of parentheses

2x+x-((4x-28))-10+8=0



We calculate terms in parentheses: -((4x-28)), so:

(4x-28)

We get rid of parentheses

4x-28

Back to the equation:

-(4x-28)



We add all the numbers together, and all the variables

3x-(4x-28)-2=0

We get rid of parentheses

3x-4x+28-2=0

We add all the numbers together, and all the variables

-1x+26=0

We move all terms containing x to the left, all other terms to the right

-x=-26

x=-26/-1

x=+26

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