(2x-10)-(x+3)=(7x-4)=

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Solution for (2x-10)-(x+3)=(7x-4)= equation:



(2x-10)-(x+3)=(7x-4)=
We move all terms to the left:
(2x-10)-(x+3)-((7x-4))=0
We get rid of parentheses
2x-x-((7x-4))-10-3=0
We calculate terms in parentheses: -((7x-4)), so:
(7x-4)
We get rid of parentheses
7x-4
Back to the equation:
-(7x-4)
We add all the numbers together, and all the variables
x-(7x-4)-13=0
We get rid of parentheses
x-7x+4-13=0
We add all the numbers together, and all the variables
-6x-9=0
We move all terms containing x to the left, all other terms to the right
-6x=9
x=9/-6
x=-1+1/2

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