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(2x-12)+(x+36)+x=180
We move all terms to the left:
(2x-12)+(x+36)+x-(180)=0
We add all the numbers together, and all the variables
x+(2x-12)+(x+36)-180=0
We get rid of parentheses
x+2x+x-12+36-180=0
We add all the numbers together, and all the variables
4x-156=0
We move all terms containing x to the left, all other terms to the right
4x=156
x=156/4
x=39
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