(2x-12)+(x-12)=42

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Solution for (2x-12)+(x-12)=42 equation: 



(2x-12)+(x-12)=42

We move all terms to the left:

(2x-12)+(x-12)-(42)=0

We get rid of parentheses

2x+x-12-12-42=0

We add all the numbers together, and all the variables

3x-66=0

We move all terms containing x to the left, all other terms to the right

3x=66

x=66/3

x=22

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