(2x-13)/5-(x-3)/11=(x-9)/5+1

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Solution for (2x-13)/5-(x-3)/11=(x-9)/5+1 equation:



(2x-13)/5-(x-3)/11=(x-9)/5+1
We move all terms to the left:
(2x-13)/5-(x-3)/11-((x-9)/5+1)=0
We calculate fractions
(22x-143)/()+(-(x-3)*5*5)/()+(-((x-9)*11)/()=0
We calculate terms in parentheses: +(-(x-3)*5*5)/(), so:
-(x-3)*5*5)/(
We multiply all the terms by the denominator
-(x-3)*5*5)
We get rid of parentheses
-x+3)*5*5
We add all the numbers together, and all the variables
-x
Back to the equation:
+(-x)
We calculate terms in parentheses: +(-((x-9)*11)/(), so:
-((x-9)*11)/(
We multiply all the terms by the denominator
-((x-9)*11)
We calculate terms in parentheses: -((x-9)*11), so:
(x-9)*11
We multiply parentheses
11x-99
Back to the equation:
-(11x-99)
We get rid of parentheses
-11x+99
Back to the equation:
+(-11x+99)
We add all the numbers together, and all the variables
(22x-143)/()+(-1x)+(-11x+99)=0
We get rid of parentheses
(22x-143)/()-1x-11x+99=0
We multiply all the terms by the denominator
(22x-143)-1x*()-11x*()+99*()=0
We add all the numbers together, and all the variables
(22x-143)-1x*()-11x*()=0
We get rid of parentheses
22x-1x*()-11x*()-143=0
We move all terms containing x to the left, all other terms to the right
22x-1x*()-11x*()=143

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