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(2x-15)(4x+1)=0
We multiply parentheses ..
(+8x^2+2x-60x-15)=0
We get rid of parentheses
8x^2+2x-60x-15=0
We add all the numbers together, and all the variables
8x^2-58x-15=0
a = 8; b = -58; c = -15;
Δ = b2-4ac
Δ = -582-4·8·(-15)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-62}{2*8}=\frac{-4}{16} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+62}{2*8}=\frac{120}{16} =7+1/2 $
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