(2x-15)/10=(x-9)/2

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Solution for (2x-15)/10=(x-9)/2 equation: 



(2x-15)/10=(x-9)/2

We move all terms to the left:

(2x-15)/10-((x-9)/2)=0

We calculate fractions


2x/()+(-((x-9)*10)/()=0



We calculate terms in parentheses: +(-((x-9)*10)/(), so:

-((x-9)*10)/(

We multiply all the terms by the denominator


-((x-9)*10)



We calculate terms in parentheses: -((x-9)*10), so:

(x-9)*10

We multiply parentheses

10x-90

Back to the equation:

-(10x-90)



We get rid of parentheses

-10x+90

Back to the equation:

+(-10x+90)



We get rid of parentheses

2x/()-10x+90=0

We multiply all the terms by the denominator


2x-10x*()+90*()=0

We add all the numbers together, and all the variables

2x-10x*()=0

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