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(2x-16)(x-30)=0
We multiply parentheses ..
(+2x^2-60x-16x+480)=0
We get rid of parentheses
2x^2-60x-16x+480=0
We add all the numbers together, and all the variables
2x^2-76x+480=0
a = 2; b = -76; c = +480;
Δ = b2-4ac
Δ = -762-4·2·480
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-44}{2*2}=\frac{32}{4} =8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+44}{2*2}=\frac{120}{4} =30 $
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