(2x-16)+(6x-18)+(2x-16)=180

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Solution for (2x-16)+(6x-18)+(2x-16)=180 equation: 



(2x-16)+(6x-18)+(2x-16)=180

We move all terms to the left:

(2x-16)+(6x-18)+(2x-16)-(180)=0

We get rid of parentheses

2x+6x+2x-16-18-16-180=0

We add all the numbers together, and all the variables

10x-230=0

We move all terms containing x to the left, all other terms to the right

10x=230

x=230/10

x=23

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