(2x-17)(x+8)=0

Solution for (2x-17)(x+8)=0 equation:

(2x-17)(x+8)=0

We multiply parentheses ..

(+2x^2+16x-17x-136)=0

We get rid of parentheses

2x^2+16x-17x-136=0

We add all the numbers together, and all the variables

2x^2-1x-136=0

a = 2; b = -1; c = -136;
Δ = b2-4ac
Δ = -12-4·2·(-136)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-33}{2*2}=\frac{-32}{4}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+33}{2*2}=\frac{34}{4}
=8+1/2
$