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(2x-17)+(x+53)(x)=180
We move all terms to the left:
(2x-17)+(x+53)(x)-(180)=0
We multiply parentheses
x^2+(2x-17)+53x-180=0
We get rid of parentheses
x^2+2x+53x-17-180=0
We add all the numbers together, and all the variables
x^2+55x-197=0
a = 1; b = 55; c = -197;
Δ = b2-4ac
Δ = 552-4·1·(-197)
Δ = 3813
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{3813}}{2*1}=\frac{-55-\sqrt{3813}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{3813}}{2*1}=\frac{-55+\sqrt{3813}}{2} $
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