(2x-18)+27x=2(14x-10)

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Solution for (2x-18)+27x=2(14x-10) equation: 



(2x-18)+27x=2(14x-10)

We move all terms to the left:

(2x-18)+27x-(2(14x-10))=0

We add all the numbers together, and all the variables

27x+(2x-18)-(2(14x-10))=0

We get rid of parentheses

27x+2x-(2(14x-10))-18=0



We calculate terms in parentheses: -(2(14x-10)), so:

2(14x-10)

We multiply parentheses

28x-20

Back to the equation:

-(28x-20)



We add all the numbers together, and all the variables

29x-(28x-20)-18=0

We get rid of parentheses

29x-28x+20-18=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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