(2x-18)/4=(3x+1)/2

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Solution for (2x-18)/4=(3x+1)/2 equation: 



(2x-18)/4=(3x+1)/2

We move all terms to the left:

(2x-18)/4-((3x+1)/2)=0

We calculate fractions


2x/()+(-((3x+1)*4)/()=0



We calculate terms in parentheses: +(-((3x+1)*4)/(), so:

-((3x+1)*4)/(

We multiply all the terms by the denominator


-((3x+1)*4)



We calculate terms in parentheses: -((3x+1)*4), so:

(3x+1)*4

We multiply parentheses

12x+4

Back to the equation:

-(12x+4)



We get rid of parentheses

-12x-4

Back to the equation:

+(-12x-4)



We get rid of parentheses

2x/()-12x-4=0

We multiply all the terms by the denominator


2x-12x*()-4*()=0

We add all the numbers together, and all the variables

2x-12x*()=0

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