(2x-18)4=(3x+1)2

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Solution for (2x-18)4=(3x+1)2 equation: 



(2x-18)4=(3x+1)2

We move all terms to the left:

(2x-18)4-((3x+1)2)=0

We multiply parentheses

8x-((3x+1)2)-72=0



We calculate terms in parentheses: -((3x+1)2), so:

(3x+1)2

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

8x-6x-2-72=0

We add all the numbers together, and all the variables

2x-74=0

We move all terms containing x to the left, all other terms to the right

2x=74

x=74/2

x=37

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