(2x-18)=(9x-16)+(3x+16)

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Solution for (2x-18)=(9x-16)+(3x+16) equation: 



(2x-18)=(9x-16)+(3x+16)

We move all terms to the left:

(2x-18)-((9x-16)+(3x+16))=0

We get rid of parentheses

2x-((9x-16)+(3x+16))-18=0



We calculate terms in parentheses: -((9x-16)+(3x+16)), so:

(9x-16)+(3x+16)

We get rid of parentheses

9x+3x-16+16

We add all the numbers together, and all the variables

12x

Back to the equation:

-(12x)



We add all the numbers together, and all the variables

-10x-18=0

We move all terms containing x to the left, all other terms to the right

-10x=18

x=18/-10

x=-1+4/5

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