(2x-2)(3x-3)=0

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Solution for (2x-2)(3x-3)=0 equation: 



(2x-2)(3x-3)=0

We multiply parentheses ..

(+6x^2-6x-6x+6)=0

We get rid of parentheses

6x^2-6x-6x+6=0

We add all the numbers together, and all the variables

6x^2-12x+6=0

a = 6; b = -12; c = +6;
Δ = b2-4ac
Δ = -122-4·6·6
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{12}=1$

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