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(2x-2)(4x+2)=(8x+3)(x-4)
We move all terms to the left:
(2x-2)(4x+2)-((8x+3)(x-4))=0
We multiply parentheses ..
(+8x^2+4x-8x-4)-((8x+3)(x-4))=0
We calculate terms in parentheses: -((8x+3)(x-4)), so:We get rid of parentheses
(8x+3)(x-4)
We multiply parentheses ..
(+8x^2-32x+3x-12)
We get rid of parentheses
8x^2-32x+3x-12
We add all the numbers together, and all the variables
8x^2-29x-12
Back to the equation:
-(8x^2-29x-12)
8x^2-8x^2+4x-8x+29x-4+12=0
We add all the numbers together, and all the variables
25x+8=0
We move all terms containing x to the left, all other terms to the right
25x=-8
x=-8/25
x=-8/25
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