(2x-2)(x+1)=0

Solution for (2x-2)(x+1)=0 equation:

Simplifying
(2x + -2)(x + 1) = 0

Reorder the terms:
(-2 + 2x)(x + 1) = 0

Reorder the terms:
(-2 + 2x)(1 + x) = 0

Multiply (-2 + 2x) * (1 + x)
(-2(1 + x) + 2x * (1 + x)) = 0
((1 * -2 + x * -2) + 2x * (1 + x)) = 0
((-2 + -2x) + 2x * (1 + x)) = 0
(-2 + -2x + (1 * 2x + x * 2x)) = 0
(-2 + -2x + (2x + 2x2)) = 0

Combine like terms: -2x + 2x = 0
(-2 + 0 + 2x2) = 0
(-2 + 2x2) = 0

Solving
-2 + 2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 2x2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 2x2 = 0 + 2
2x2 = 0 + 2

Combine like terms: 0 + 2 = 2
2x2 = 2

Divide each side by '2'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}