(2x-2)(x+3)=x(1+4x)/2+1

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Solution for (2x-2)(x+3)=x(1+4x)/2+1 equation: 



(2x-2)(x+3)=x(1+4x)/2+1

We move all terms to the left:

(2x-2)(x+3)-(x(1+4x)/2+1)=0

We add all the numbers together, and all the variables

(2x-2)(x+3)-(x(4x+1)/2+1)=0

We multiply parentheses ..

(+2x^2+6x-2x-6)-(x(4x+1)/2+1)=0

We multiply all the terms by the denominator


((+2x^2+6x-2x-6))*2+1)-(x(4x+1)=0

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