(2x-2)(x+5)=-10

Solution for (2x-2)(x+5)=-10 equation:

(2x-2)(x+5)=-10

We move all terms to the left:

(2x-2)(x+5)-(-10)=0

We add all the numbers together, and all the variables

(2x-2)(x+5)+10=0

We multiply parentheses ..

(+2x^2+10x-2x-10)+10=0

We get rid of parentheses

2x^2+10x-2x-10+10=0

We add all the numbers together, and all the variables

2x^2+8x=0

a = 2; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·2·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*2}=\frac{0}{4}
=0
$