(2x-2)+(3x+23)=(x+12)+(4x+11)

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Solution for (2x-2)+(3x+23)=(x+12)+(4x+11) equation: 



(2x-2)+(3x+23)=(x+12)+(4x+11)

We move all terms to the left:

(2x-2)+(3x+23)-((x+12)+(4x+11))=0

We get rid of parentheses

2x+3x-((x+12)+(4x+11))-2+23=0



We calculate terms in parentheses: -((x+12)+(4x+11)), so:

(x+12)+(4x+11)

We get rid of parentheses

x+4x+12+11

We add all the numbers together, and all the variables

5x+23

Back to the equation:

-(5x+23)



We add all the numbers together, and all the variables

5x-(5x+23)+21=0

We get rid of parentheses

5x-5x-23+21=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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