(2x-2)+(4x+4)-(5x-3)=(3x-4)+(6x+2)-9

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Solution for (2x-2)+(4x+4)-(5x-3)=(3x-4)+(6x+2)-9 equation: 



(2x-2)+(4x+4)-(5x-3)=(3x-4)+(6x+2)-9

We move all terms to the left:

(2x-2)+(4x+4)-(5x-3)-((3x-4)+(6x+2)-9)=0

We get rid of parentheses

2x+4x-5x-((3x-4)+(6x+2)-9)-2+4+3=0



We calculate terms in parentheses: -((3x-4)+(6x+2)-9), so:

(3x-4)+(6x+2)-9

We get rid of parentheses

3x+6x-4+2-9

We add all the numbers together, and all the variables

9x-11

Back to the equation:

-(9x-11)



We add all the numbers together, and all the variables

x-(9x-11)+5=0

We get rid of parentheses

x-9x+11+5=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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