(2x-2)+(x+1)+(x+1)+x=(2x-9)+(x+1)+(x+8)+x

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Solution for (2x-2)+(x+1)+(x+1)+x=(2x-9)+(x+1)+(x+8)+x equation: 



(2x-2)+(x+1)+(x+1)+x=(2x-9)+(x+1)+(x+8)+x

We move all terms to the left:

(2x-2)+(x+1)+(x+1)+x-((2x-9)+(x+1)+(x+8)+x)=0

We add all the numbers together, and all the variables

x+(2x-2)+(x+1)+(x+1)-((2x-9)+(x+1)+(x+8)+x)=0

We get rid of parentheses

x+2x+x+x-((2x-9)+(x+1)+(x+8)+x)-2+1+1=0



We calculate terms in parentheses: -((2x-9)+(x+1)+(x+8)+x), so:

(2x-9)+(x+1)+(x+8)+x

We add all the numbers together, and all the variables

x+(2x-9)+(x+1)+(x+8)

We get rid of parentheses

x+2x+x+x-9+1+8

We add all the numbers together, and all the variables

5x

Back to the equation:

-(5x)



We add all the numbers together, and all the variables

=0

x=0/1

x=0

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