(2x-2)+(x+1)=(2x-9)+(x+8)

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Solution for (2x-2)+(x+1)=(2x-9)+(x+8) equation: 



(2x-2)+(x+1)=(2x-9)+(x+8)

We move all terms to the left:

(2x-2)+(x+1)-((2x-9)+(x+8))=0

We get rid of parentheses

2x+x-((2x-9)+(x+8))-2+1=0



We calculate terms in parentheses: -((2x-9)+(x+8)), so:

(2x-9)+(x+8)

We get rid of parentheses

2x+x-9+8

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We add all the numbers together, and all the variables

3x-(3x-1)-1=0

We get rid of parentheses

3x-3x+1-1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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