(2x-2)+x+1+x+(x+1)=(2x-9)+(x+1)+(x+8)+x

Solution for (2x-2)+x+1+x+(x+1)=(2x-9)+(x+1)+(x+8)+x equation:

(2x-2)+x+1+x+(x+1)=(2x-9)+(x+1)+(x+8)+x

We move all terms to the left:

(2x-2)+x+1+x+(x+1)-((2x-9)+(x+1)+(x+8)+x)=0

We add all the numbers together, and all the variables

2x+(2x-2)+(x+1)-((2x-9)+(x+1)+(x+8)+x)+1=0

We get rid of parentheses

2x+2x+x-((2x-9)+(x+1)+(x+8)+x)-2+1+1=0


We calculate terms in parentheses: -((2x-9)+(x+1)+(x+8)+x), so:

(2x-9)+(x+1)+(x+8)+x

We add all the numbers together, and all the variables

x+(2x-9)+(x+1)+(x+8)

We get rid of parentheses

x+2x+x+x-9+1+8

We add all the numbers together, and all the variables

5x

Back to the equation:

-(5x)


We add all the numbers together, and all the variables

=0

x=0/1

x=0