(2x-2)-(3x-15)=1/6

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Solution for (2x-2)-(3x-15)=1/6 equation:



(2x-2)-(3x-15)=1/6
We move all terms to the left:
(2x-2)-(3x-15)-(1/6)=0
We add all the numbers together, and all the variables
(2x-2)-(3x-15)-(+1/6)=0
We get rid of parentheses
2x-3x-2+15-1/6=0
We multiply all the terms by the denominator
2x*6-3x*6-1-2*6+15*6=0
We add all the numbers together, and all the variables
2x*6-3x*6+77=0
Wy multiply elements
12x-18x+77=0
We add all the numbers together, and all the variables
-6x+77=0
We move all terms containing x to the left, all other terms to the right
-6x=-77
x=-77/-6
x=12+5/6

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