(2x-2)/14=(2x-4)/16

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Solution for (2x-2)/14=(2x-4)/16 equation: 



(2x-2)/14=(2x-4)/16

We move all terms to the left:

(2x-2)/14-((2x-4)/16)=0

We calculate fractions


2x/()+(-((2x-4)*14)/()=0



We calculate terms in parentheses: +(-((2x-4)*14)/(), so:

-((2x-4)*14)/(

We multiply all the terms by the denominator


-((2x-4)*14)



We calculate terms in parentheses: -((2x-4)*14), so:

(2x-4)*14

We multiply parentheses

28x-56

Back to the equation:

-(28x-56)



We get rid of parentheses

-28x+56

Back to the equation:

+(-28x+56)



We get rid of parentheses

2x/()-28x+56=0

We multiply all the terms by the denominator


2x-28x*()+56*()=0

We add all the numbers together, and all the variables

2x-28x*()=0

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