(2x-2)/3+5=1;x

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Solution for (2x-2)/3+5=1;x equation: 



(2x-2)/3+5=1x

We move all terms to the left:

(2x-2)/3+5-(1x)=0

We add all the numbers together, and all the variables

-1x+(2x-2)/3+5=0

We multiply all the terms by the denominator


-1x*3+(2x-2)+5*3=0

We add all the numbers together, and all the variables

-1x*3+(2x-2)+15=0

Wy multiply elements

-3x+(2x-2)+15=0

We get rid of parentheses

-3x+2x-2+15=0

We add all the numbers together, and all the variables

-1x+13=0

We move all terms containing x to the left, all other terms to the right

-x=-13

x=-13/-1

x=+13

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