(2x-2)/6=(x-3)/5

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Solution for (2x-2)/6=(x-3)/5 equation: 



(2x-2)/6=(x-3)/5

We move all terms to the left:

(2x-2)/6-((x-3)/5)=0

We calculate fractions


2x/()+(-((x-3)*6)/()=0



We calculate terms in parentheses: +(-((x-3)*6)/(), so:

-((x-3)*6)/(

We multiply all the terms by the denominator


-((x-3)*6)



We calculate terms in parentheses: -((x-3)*6), so:

(x-3)*6

We multiply parentheses

6x-18

Back to the equation:

-(6x-18)



We get rid of parentheses

-6x+18

Back to the equation:

+(-6x+18)



We get rid of parentheses

2x/()-6x+18=0

We multiply all the terms by the denominator


2x-6x*()+18*()=0

We add all the numbers together, and all the variables

2x-6x*()=0

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