(2x-2)=(7x-4)+(2x+16)

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Solution for (2x-2)=(7x-4)+(2x+16) equation: 



(2x-2)=(7x-4)+(2x+16)

We move all terms to the left:

(2x-2)-((7x-4)+(2x+16))=0

We get rid of parentheses

2x-((7x-4)+(2x+16))-2=0



We calculate terms in parentheses: -((7x-4)+(2x+16)), so:

(7x-4)+(2x+16)

We get rid of parentheses

7x+2x-4+16

We add all the numbers together, and all the variables

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

2x-9x-12-2=0

We add all the numbers together, and all the variables

-7x-14=0

We move all terms containing x to the left, all other terms to the right

-7x=14

x=14/-7

x=-2

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