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(2x-20)(2x-26)=432
We move all terms to the left:
(2x-20)(2x-26)-(432)=0
We multiply parentheses ..
(+4x^2-52x-40x+520)-432=0
We get rid of parentheses
4x^2-52x-40x+520-432=0
We add all the numbers together, and all the variables
4x^2-92x+88=0
a = 4; b = -92; c = +88;
Δ = b2-4ac
Δ = -922-4·4·88
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-84}{2*4}=\frac{8}{8} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+84}{2*4}=\frac{176}{8} =22 $
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