(2x-20)+(2x+10)+x+2x+(x+30)=540

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Solution for (2x-20)+(2x+10)+x+2x+(x+30)=540 equation: 



(2x-20)+(2x+10)+x+2x+(x+30)=540

We move all terms to the left:

(2x-20)+(2x+10)+x+2x+(x+30)-(540)=0

We add all the numbers together, and all the variables

3x+(2x-20)+(2x+10)+(x+30)-540=0

We get rid of parentheses

3x+2x+2x+x-20+10+30-540=0

We add all the numbers together, and all the variables

8x-520=0

We move all terms containing x to the left, all other terms to the right

8x=520

x=520/8

x=65

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