(2x-20)+(2x-20)+(3x+5)=180

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Solution for (2x-20)+(2x-20)+(3x+5)=180 equation: 



(2x-20)+(2x-20)+(3x+5)=180

We move all terms to the left:

(2x-20)+(2x-20)+(3x+5)-(180)=0

We get rid of parentheses

2x+2x+3x-20-20+5-180=0

We add all the numbers together, and all the variables

7x-215=0

We move all terms containing x to the left, all other terms to the right

7x=215

x=215/7

x=30+5/7

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