(2x-20)+(3x+5)+(3x+5)=180

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Solution for (2x-20)+(3x+5)+(3x+5)=180 equation: 



(2x-20)+(3x+5)+(3x+5)=180

We move all terms to the left:

(2x-20)+(3x+5)+(3x+5)-(180)=0

We get rid of parentheses

2x+3x+3x-20+5+5-180=0

We add all the numbers together, and all the variables

8x-190=0

We move all terms containing x to the left, all other terms to the right

8x=190

x=190/8

x=23+3/4

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