(2x-20)+(x+10)=270

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Solution for (2x-20)+(x+10)=270 equation: 



(2x-20)+(x+10)=270

We move all terms to the left:

(2x-20)+(x+10)-(270)=0

We get rid of parentheses

2x+x-20+10-270=0

We add all the numbers together, and all the variables

3x-280=0

We move all terms containing x to the left, all other terms to the right

3x=280

x=280/3

x=93+1/3

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