(2x-20)+(x+56)+(x)=180

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Solution for (2x-20)+(x+56)+(x)=180 equation: 



(2x-20)+(x+56)+(x)=180

We move all terms to the left:

(2x-20)+(x+56)+(x)-(180)=0

We add all the numbers together, and all the variables

x+(2x-20)+(x+56)-180=0

We get rid of parentheses

x+2x+x-20+56-180=0

We add all the numbers together, and all the variables

4x-144=0

We move all terms containing x to the left, all other terms to the right

4x=144

x=144/4

x=36

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