(2x-20)+x=160

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Solution for (2x-20)+x=160 equation: 



(2x-20)+x=160

We move all terms to the left:

(2x-20)+x-(160)=0

We add all the numbers together, and all the variables

x+(2x-20)-160=0

We get rid of parentheses

x+2x-20-160=0

We add all the numbers together, and all the variables

3x-180=0

We move all terms containing x to the left, all other terms to the right

3x=180

x=180/3

x=60

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