(2x-20)/8=-5

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Solution for (2x-20)/8=-5 equation: 



(2x-20)/8=-5

We move all terms to the left:

(2x-20)/8-(-5)=0

We add all the numbers together, and all the variables

(2x-20)/8+5=0

We multiply all the terms by the denominator


(2x-20)+5*8=0

We add all the numbers together, and all the variables

(2x-20)+40=0

We get rid of parentheses

2x-20+40=0

We add all the numbers together, and all the variables

2x+20=0

We move all terms containing x to the left, all other terms to the right

2x=-20

x=-20/2

x=-10

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