(2x-2000)+(2x-2000)+(2x-2000)=5000

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Solution for (2x-2000)+(2x-2000)+(2x-2000)=5000 equation: 



(2x-2000)+(2x-2000)+(2x-2000)=5000

We move all terms to the left:

(2x-2000)+(2x-2000)+(2x-2000)-(5000)=0

We get rid of parentheses

2x+2x+2x-2000-2000-2000-5000=0

We add all the numbers together, and all the variables

6x-11000=0

We move all terms containing x to the left, all other terms to the right

6x=11000

x=11000/6

x=1833+1/3

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