(2x-22)=(x+5)

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Solution for (2x-22)=(x+5) equation: 



(2x-22)=(x+5)

We move all terms to the left:

(2x-22)-((x+5))=0

We get rid of parentheses

2x-((x+5))-22=0



We calculate terms in parentheses: -((x+5)), so:

(x+5)

We get rid of parentheses

x+5

Back to the equation:

-(x+5)



We get rid of parentheses

2x-x-5-22=0

We add all the numbers together, and all the variables

x-27=0

We move all terms containing x to the left, all other terms to the right

x=27

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