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(2x-22)=(x+5)
We move all terms to the left:
(2x-22)-((x+5))=0
We get rid of parentheses
2x-((x+5))-22=0
We calculate terms in parentheses: -((x+5)), so:We get rid of parentheses
(x+5)
We get rid of parentheses
x+5
Back to the equation:
-(x+5)
2x-x-5-22=0
We add all the numbers together, and all the variables
x-27=0
We move all terms containing x to the left, all other terms to the right
x=27
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