(2x-27)=(4x+12)

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Solution for (2x-27)=(4x+12) equation: 



(2x-27)=(4x+12)

We move all terms to the left:

(2x-27)-((4x+12))=0

We get rid of parentheses

2x-((4x+12))-27=0



We calculate terms in parentheses: -((4x+12)), so:

(4x+12)

We get rid of parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

2x-4x-12-27=0

We add all the numbers together, and all the variables

-2x-39=0

We move all terms containing x to the left, all other terms to the right

-2x=39

x=39/-2

x=-19+1/2

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