(2x-3)(2x+1)-1=4x(x-5)

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Solution for (2x-3)(2x+1)-1=4x(x-5) equation: 



(2x-3)(2x+1)-1=4x(x-5)

We move all terms to the left:

(2x-3)(2x+1)-1-(4x(x-5))=0

We multiply parentheses ..

(+4x^2+2x-6x-3)-(4x(x-5))-1=0



We calculate terms in parentheses: -(4x(x-5)), so:

4x(x-5)

We multiply parentheses

4x^2-20x

Back to the equation:

-(4x^2-20x)



We get rid of parentheses

4x^2-4x^2+2x-6x+20x-3-1=0

We add all the numbers together, and all the variables

16x-4=0

We move all terms containing x to the left, all other terms to the right

16x=4

x=4/16

x=1/4

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